this is a combination question since the order does not matter
Prob(4clubs out of 10cards)
= C(13,4)*C(39,6)/C(52,10)
= 715(3262623)/(1.582x10^10)
= .1475
let me know if my choice of C(n,r)'s don't make sense to you.
Ten cards are selected without replacement from a standard 52 card deck that contains 13 clubs and 39 other cards. What is the probability
that 4 of them are clubs?
2 answers
your doing independent event is different from my math class i don't get it my got different from ur math hmmmm