C=(F-32)×5/9
Since, C=2F(given)
Hence,
2F=(F-32)×5/9
18F=(F-32)×5
18F=5F-160
13F=-160
F=-160/13
Temperature readings on the Fahrenheit and Celsius scales are related by the formula 𝐶 =
5
9
(𝐹 − 32).
Determine when the temperature reading on the Celsius scale is twice the temperature reading on the
Fahrenheit scale.
1 answer