Temperature of Bunsen Burner Flame:

Question

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(couldn't put the link so I spaced it out)

My data Table:
Type of metal used: Cu
Mass of metal object: 75.4 g
Sp.ht of metal object: 0.385 J/g °C
Mass of empty Styrofoam: 2.9 g
Mass of Styrofoam cup & water: 184.9 g
Temp of water (before): 22.9 °C
Temp of water (after) : 49.1 °C

1. Calculate the change in temp of water.
Answer: 49.1 °C-22.9 °C= 26.2 °C .. (It's simply - the final and initial correct)

2. Determine initial mass of water heated?

3. Calculate the heat gained by the water. (Mass * ΔT * Sp.ht=)
184.9 g * 26.2 °C* 0.385 J/g°C = 187... Is this right because I'm not sure!

4. Calculate the temp of Hot metal Object? (heat lost by metal=heat gained by water)
heat lost by metal =187...

Calculations Table:
Change in temp of water = 26.2°C
Mass of water initial= 184.9-2.9g= 182 g
Heat absorbed by water= ?
Temp of hot, metal object = ? °C
Temp of Bunsen burner flame= °C

Answer 1

Forget this... °.. I accidentally put that & also for #3, it should be mass*change in temp*sp.ht