Temp c KBr

20 65
40 80
60 90
80 100
100 110

At 100 C, 10.5 g KBr/10gH2O = 105 g/100 g (just multiply the top and the bottom by 10 to give you 100 g H2O)

B) Since the solubility at 100C is actually 110, no, it isn't saturated (105 is less that 110).

C) Yes, because the solubility is 80 g/100 g at 40C.

D) At 40 C, 10g of H2O could dissolve 8 g of KBr. So, 10.5 - 8 = 1.5 g of solid formed.

I am not sure if I did the last part right?

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