To determine whether \( c = -5 \) is a solution to the equation \( -6c = 20 - 2c \), we can substitute \(-5\) for \(c\) in the equation.
Starting with the left side of the equation: \[ -6c = -6(-5) = 30 \]
Now, for the right side of the equation: \[ 20 - 2c = 20 - 2(-5) = 20 + 10 = 30 \]
Now we can compare both sides: \[ 30 = 30 \]
Since both sides are equal, \( c = -5 \) is indeed a solution.
Answer: solution