Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?
2 answers
Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?
no intervals but here is how you do it.
k = 0.693/t1/2
ln(No/N) = kt
No = 280 mg
N = unknown
k from above
t = intervals in the problem (in hours).
k = 0.693/t1/2
ln(No/N) = kt
No = 280 mg
N = unknown
k from above
t = intervals in the problem (in hours).
1 answer