To determine the approximate percentage of technetium-99m that will remain in the patient's body after 12 hours, we need to take into account the half-life of technetium-99m.
Since the half-life of technetium-99m is 6 hours, after 6 hours, half of the initial dose will remain in the patient's body.
After another 6 hours (for a total of 12 hours), another half of the remaining dose will remain in the patient's body.
Therefore, after 12 hours, approximately 25.0% of the technetium-99m will remain in the patient's body (half of the initial dose).
So the correct answer is 25.0%.
Technetium-99m is a radioactive isotope frequently employed in medical applications as a radioactive tracer. A radioactive tracer involves introducing isotype into the body to facilitate the generation of diagnostic images for health condition assessment. Technetium-99m possesses a half life of 6 hours. I have a patient is administered a dose of technetium-99m in the morning what approximate percentage of the technetium-99m will remain within the patient’s body after 12 hours
12.5%
25.0%
6.25%
93.8%
1 answer
1 answer