tanx +cotx=secx cscx
2 answers
Yes, this seems to be a true statement.
start with the LS
LS = tanx + cotx
= sinx/cosx + cosx/sinx
your LCD is sinxcosx
= (sin^2 x + cos^2 x)/(sinxcosx)
= ....
you should be able to finish it
LS = tanx + cotx
= sinx/cosx + cosx/sinx
your LCD is sinxcosx
= (sin^2 x + cos^2 x)/(sinxcosx)
= ....
you should be able to finish it