tanA+sinA=p, tanA-sinA=q shows that p^2+q^2

Answer 1

let
c = tan A
d = sin A

P = c + d so p^2 = c^2 + 2 c d + d^2
q = c - d so q^2 = c^2 - 2 c d + d^2

p^2+q^2 = 2 (c^2 + d^2)

= 2 (tan^2 A + sin^2 A)

so what is the question?