Asked by N
(tan/cot)- (sec/ cos)
Also I need help with tan sin +cos = sec
Also I need help with tan sin +cos = sec
Answers
Answered by
Reiny
retype in proper form.
Are we solving or proving an identity?
Are we solving or proving an identity?
Answered by
Ehsan
tan = sin(x)/cos(x)
cot = cos(x)/sin(x)
sec = 1/cos(x)
(sin(x))^2 + (cos(x))^2 = 1
tan(x)/cot(x) - sec(x)/cos(x)
= (sin(x))^2/(cos(x))^2 - 1/(cos(x))^2
= ((sin(x))^2-1)/(cos(x))^2
= (cos(x))^2/(cos(x)^2) = 1
tan(x).sin(x) + cos(x)
= (sin(x))^2/cos(x) + cos(x)
= ((sin(x))^2 + (cos(x))^2)/cos(x)
= 1/cos(x) = sec(x)
Hope this helps!
cot = cos(x)/sin(x)
sec = 1/cos(x)
(sin(x))^2 + (cos(x))^2 = 1
tan(x)/cot(x) - sec(x)/cos(x)
= (sin(x))^2/(cos(x))^2 - 1/(cos(x))^2
= ((sin(x))^2-1)/(cos(x))^2
= (cos(x))^2/(cos(x)^2) = 1
tan(x).sin(x) + cos(x)
= (sin(x))^2/cos(x) + cos(x)
= ((sin(x))^2 + (cos(x))^2)/cos(x)
= 1/cos(x) = sec(x)
Hope this helps!
Answered by
N
Proving it!(:
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