draw your triangles in standard position. It will be clear that
sinA = 4/√41
cosA = -5/√41
sinB = -12/13
cosB = -5/13
Now just plug that into the formula for cos(A+B)
Although I suspect a typo...
tan A=-4/5;A in Quadrant 2 and cos B=-5/13: B in Quadrant 3.
What is the exact value of the expression cos(A+B)?
2 answers
73*41^1/2/533