Tan7pi/4=Tan(pi+3pi/4) lies in IVQdt and is =-Tan pi/4.
Tan 5pi/4=tan (pi+pi/4) lis in IIIQdt and is=tan pi/4, hence your ans is correct.
tan(7π/4) + tan(5π/4)
Does this = 0
2 answers
Tan (7pi/4)+ Tan (5pi/4)
=Tan (pi+3pi/4)+ Tan (pi+pi/4)
=-Tan (pi/4)+ Tan (pi/4)
= 0
=Tan (pi+3pi/4)+ Tan (pi+pi/4)
=-Tan (pi/4)+ Tan (pi/4)
= 0