(tan/(1+sec)) + ((1+sec)/tan) = 2csc

Question

(Show all work please.)

Answer 1

I see tangents and secants on the left side, so I suspect to use the identity
tan^2x + 1 = sec^2x

LS
= tanx(1+secx) + (1+secx)/tanx
= (tan^2x + 1 + 2secx + sec^2x)/(tanx(1+secx))
= (sec^2x + 2secx + sec^2x)/(tanx(1+secx))
= (2sec^2x + 2secx)/(tanx(1+secx))
= 2secx(secx + 1)/(tanx(1+secx))
= 2secx/tanx
= (2/cosx)÷(sinx/cosx)
= (2/cosx)(cosx/sinx)
= 2/sinx
= 2cscx
= RS

Q.E.D.

Answer 2

y=2sec(1/3x)