To dilate a triangle around the origin (0, 0) by a scale factor of 4, you multiply each of the triangle's vertices by the scale factor.
The original vertices of the triangle are:
- A (12, 0)
- B (5, 0)
- C (4, 3)
Now, let's perform the dilation for each vertex:
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For vertex A (12, 0): \( A' = (12 \times 4, 0 \times 4) = (48, 0) \)
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For vertex B (5, 0): \( B' = (5 \times 4, 0 \times 4) = (20, 0) \)
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For vertex C (4, 3): \( C' = (4 \times 4, 3 \times 4) = (16, 12) \)
Thus, the new vertices of the dilated triangle are:
- A' (48, 0)
- B' (20, 0)
- C' (16, 12)
Now let’s see if this matches any of the provided responses:
- (18,0), (54,0), and (1,34)
- (92,4), (9,4), and (8,7)
- (−72,−4), (1,−4), and (0,−1)
- (2,0), (20,0), and (16,12)
The correct vertices after dilation are (48, 0), (20, 0), and (16, 12). However, none of the provided options match the calculated results precisely.
It seems that the correct answer based on the calculations for the dilation of triangle vertices does not match any option exactly. The closest match concerning two vertices is (20, 0) and (16, 12), but the third vertex was miscalculated in the options provided. Please double-check the question's options and confirm whether any typographical error exists.