Tamara, Payton, Krish, and Haruki are analyzing the solution sets to the following linear equations. Tamara says that Equation A and Equation C have the same solution. Payton says Equation B and Equation C have the same solution. Krish says all three have the same solution. Haruki says that none of the equations have the same solution. Identify who is correct about the linear equations. Equation A: 3(4−5h)−7=−12+2h Equation B: 2(p−3)−1=6p+142 Equation C: 23v−3+83=−1 (1 point) Responses Payton Payton Krish Krish Haruki Haruki Tamara

1 answer

Let's solve the equations to determine who is correct about their solution sets.

Equation A: \[ 3(4 - 5h) - 7 = -12 + 2h \] Expanding the left side: \[ 12 - 15h - 7 = -12 + 2h \] Simplifying: \[ 5 - 15h = -12 + 2h \] Bringing the \(h\) terms together: \[ 5 + 12 = 15h + 2h \] \[ 17 = 17h \] Dividing by 17: \[ h = 1 \]

Equation B: \[ 2(p - 3) - 1 = 6p + 142 \] Expanding the left side: \[ 2p - 6 - 1 = 6p + 142 \] Simplifying: \[ 2p - 7 = 6p + 142 \] Bringing the \(p\) terms together: \[ -7 - 142 = 6p - 2p \] \[ -149 = 4p \] Dividing by 4: \[ p = -\frac{149}{4} \]

Equation C: \[ 23v - 3 + 83 = -1 \] Combining the constants: \[ 23v + 80 = -1 \] Subtracting 80 from both sides: \[ 23v = -1 - 80 \] \[ 23v = -81 \] Dividing by 23: \[ v = -\frac{81}{23} \]

Now we have the solutions:

  • Equation A: \( h = 1 \)
  • Equation B: \( p = -\frac{149}{4} \)
  • Equation C: \( v = -\frac{81}{23} \)

Next, we compare the solutions:

  • Tamara's claim (Equation A and C have the same solution) is incorrect.
  • Payton's claim (Equation B and C have the same solution) is incorrect.
  • Krish's claim (all three have the same solution) is incorrect.
  • Haruki's claim (none of the equations have the same solution) is correct.

Therefore, Haruki is correct that none of the equations have the same solution.