Let's analyze each of the equations to determine their solution sets.
Equation A:
\[ 3(4 - 5h) - 7 = -12 + 2h \] First, we'll simplify the left-hand side:
- Distribute: \[ 3(4) - 3(5h) - 7 = -12 + 2h \] \[ 12 - 15h - 7 = -12 + 2h \]
- Combine like terms: \[ 5 - 15h = -12 + 2h \]
- Add \(15h\) to both sides: \[ 5 = -12 + 17h \]
- Add \(12\) to both sides: \[ 17 = 17h \]
- Divide by \(17\): \[ h = 1 \]
So, the solution for Equation A is \( h = 1 \).
Equation B:
\[ 2(p - 3) - 1 = 6p + \frac{14}{2} \] We'll simplify the left-hand side as follows:
- Distribute: \[ 2p - 6 - 1 = 6p + 7 \]
- Combine like terms: \[ 2p - 7 = 6p + 7 \]
- Subtract \(2p\) from both sides: \[ -7 = 4p + 7 \]
- Subtract \(7\) from both sides: \[ -14 = 4p \]
- Divide by \(4\): \[ p = -\frac{14}{4} \] \[ p = -\frac{7}{2} \]
So, the solution for Equation B is \( p = -\frac{7}{2} \).
Equation C:
\[ \frac{2}{3}v - 3 + \frac{8}{3} = -1 \] Combine like terms on the left-hand side:
- Convert \(-3\) to a fraction: \[ -3 = -\frac{9}{3} \] So the equation is: \[ \frac{2}{3}v - \frac{9}{3} + \frac{8}{3} = -1 \]
- Combine the constants: \[ \frac{2}{3}v - \frac{1}{3} = -1 \]
- Add \(\frac{1}{3}\) to both sides: \[ \frac{2}{3}v = -1 + \frac{1}{3} \] Convert \(-1\) into thirds: \[ -1 = -\frac{3}{3} \] Therefore: \[ \frac{2}{3}v = -\frac{3}{3} + \frac{1}{3} = -\frac{2}{3} \]
- Multiply by \(\frac{3}{2}\): \[ v = -1 \]
So, the solution for Equation C is \( v = -1 \).
Summary of Solutions:
- Equation A: \( h = 1 \)
- Equation B: \( p = -\frac{7}{2} \)
- Equation C: \( v = -1 \)
Conclusion:
- Tamara: Incorrect (A and C have different solutions)
- Payton: Incorrect (B and C have different solutions)
- Krish: Incorrect (All three have different solutions)
- Haruki: Correct (None of the equations have the same solution)
Thus, Haruki is the one who is correct.