Tamara, Payton, Krish, and Haruki are analyzing the solution sets to the following linear equations. Tamara says that Equation A and Equation C have the same solution. Payton says Equation B and Equation C have the same solution. Krish says all three have the same solution. Haruki says that none of the equations have the same solution. Identify who is correct about the linear equations.

Equation A: 3(4−5h)−7=−12+2h

Equation B: 2(p−3)−1=6p+142

Equation C: 23v−3+83=−1

(1 point)
Responses

Haruki
Haruki

Payton
Payton

Tamara
Tamara

Krish

1 answer

To determine who is correct about the solution sets of the given equations, we need to solve each equation one by one.

Equation A:
\[ 3(4 - 5h) - 7 = -12 + 2h \] Distributing the left side: \[ 12 - 15h - 7 = -12 + 2h \] This simplifies to: \[ 5 - 15h = -12 + 2h \] Now, move all terms involving \(h\) to one side and constant terms to the other side: \[ 5 + 12 = 15h + 2h \] \[ 17 = 17h \] \[ h = 1 \]

Equation B: \[ 2(p - 3) - 1 = 6p + 142 \] Distributing the left side: \[ 2p - 6 - 1 = 6p + 142 \] Simplifying gives us: \[ 2p - 7 = 6p + 142 \] Rearranging terms: \[ -7 - 142 = 6p - 2p \] \[ -149 = 4p \] \[ p = -\frac{149}{4} \]

Equation C: \[ 23v - 3 + 83 = -1 \] This simplifies to: \[ 23v + 80 = -1 \] Subtract 80 from both sides: \[ 23v = -1 - 80 \] \[ 23v = -81 \] \[ v = -\frac{81}{23} \]

Solution Summary:

  • Equation A has the solution \(h = 1\)
  • Equation B has the solution \(p = -\frac{149}{4}\)
  • Equation C has the solution \(v = -\frac{81}{23}\)

Now, comparing the solutions:

  • Tamara claims A and C have the same solution, which is incorrect.
  • Payton claims B and C have the same solution, which is incorrect.
  • Krish claims all three equations have the same solution, which is incorrect.
  • Haruki claims none of the equations have the same solution, which is correct.

Therefore, the correct answer is:

Haruki

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