Tamara is analyzing a line that passes through the point (−5,3)

Question

and has a slope of −1
. How should she write the equation of the line in slope-intercept form?(1 point)
Responses

y=x−1
y equals x minus 1

y=−x−5
y equals negative x minus 5

y=−x+3
y equals negative x plus 3

y=−x−2

Answer 1

To find the equation of the line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we can use the slope and the given point.

Given:

• Slope (m) = -1
• Point (x, y) = (−5, 3)

Using the point-slope form of the equation of a line, which is given by:

\[ y - y_1 = m(x - x_1) \]

Substituting in the values:

\[ y - 3 = -1(x - (-5)) \]

This simplifies to:

\[ y - 3 = -1(x + 5) \]

Distributing the -1:

\[ y - 3 = -x - 5 \]

Adding 3 to both sides:

\[ y = -x - 2 \]

So, the equation of the line in slope-intercept form is:

y = -x - 2

The correct response is:

y = −x − 2.