To write the equation of a line in slope-intercept form (y = mx + b), where \( m \) is the slope and \( b \) is the y-intercept, we can use the given point and slope.
The slope \( m \) is -1, and the line passes through the point (-5, 3).
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Start with the slope-intercept equation: \[ y = mx + b \]
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Substitute the slope: \[ y = -1x + b \] or \[ y = -x + b \]
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Now, use the point (-5, 3) to find \( b \). Substitute \( x = -5 \) and \( y = 3 \) into the equation: \[ 3 = -(-5) + b \] \[ 3 = 5 + b \]
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Solve for \( b \): \[ b = 3 - 5 \] \[ b = -2 \]
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Now substitute \( b \) back into the equation: \[ y = -x - 2 \]
Thus, the equation of the line in slope-intercept form is: \[ y = -x - 2 \]
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