talk like a 8th grader
Consider a galvanic cell with a beaker of Chromium(III) nitrate Cr(NO3)3 and a beaker of Copper(II) nitrate Cu(NO3)2. The Chromium(III) nitrate beaker contains a strip of chromium, and the Copper(II) nitrate cell contains a strip of copper. A wire runs between the strips. The reaction that occurs is as follows: 2Cr(s) + 3Cu2+(aq) → 2Cr3+(aq) + 3Cu(s) In three to five sentences, list which electrode is the anode and which is the cathode and the half reactions that occur at each electrode.
1 answer
So like, in this science experiment, we got this cell thingy with two beakers. One beaker has Chromium(III) nitrate and a strip of chromium, and the other beaker has Copper(II) nitrate and a strip of copper. There's a wire connecting the strips. The reaction that happens is like 2Cr(s) + 3Cu2+(aq) → 2Cr3+(aq) + 3Cu(s). I think the chromium strip is the anode and the copper strip is the cathode. At the anode, the half reaction is 2Cr(s) → 2Cr3+(aq) + 6e-. At the cathode, the half reaction is 3Cu2+(aq) + 6e- → 3Cu(s).