takes 190. seconds for a sample of carbon dioxide to effuse through a porous plug and 295 seconds for the same volume of an unknown gas to effuse under the same conditions. What is the molar mass of the unknown gas? Enter your answer to 3 significant figures.

Answer 1

rate1/rate2 = sqrt(M2/M1)
I would assume some convenient volume such as 190 mL so
rate 1 = 190mL/190 sec = 1 mL/1 sec)
rate 2 = 190 mL/295 sec = ?
Substitute and solve for M2.
M1 = 44

Answer 2

If u take the porous membrane of porous of 190 sec and 295 sec I got stuck