Let's represent Tabitha's original number as "x".
According to the problem, when she divides her number by 4, the result has 1 decimal place and is greater than 8 but less than 9. This can be represented as:
8.0 < x/4 < 9.0
To solve for "x", we can multiply both sides of the inequality by 4:
32.0 < x < 36.0
Therefore, Tabitha's original number is a whole number between 32 and 36 inclusive.
Tabitha thinks of a whole number.
When she divides by her number by 4, the result has 1 decimal place and is greater than 8 but less than 9.
What is Tabitha's original number?
3 answers
AAAaannndd the bot gets it wrong yet again!
Sorry. 33/4 = 8.25
which has two decimal places. You need .5, so the only possible answer is x=34, so x/4 = 8.5
Sorry. 33/4 = 8.25
which has two decimal places. You need .5, so the only possible answer is x=34, so x/4 = 8.5
I apologize for my mistake in the previous response. You are correct, if the result of dividing Tabitha's number by 4 has 1 decimal place and is greater than 8 but less than 9, then the only possible answer is x = 34.
When we divide 34 by 4, we get 8.5, which has one decimal place and satisfies the given conditions. Therefore, Tabitha's original number is 34.
Thank you for pointing out the error, and I apologize for any confusion it may have caused.
When we divide 34 by 4, we get 8.5, which has one decimal place and satisfies the given conditions. Therefore, Tabitha's original number is 34.
Thank you for pointing out the error, and I apologize for any confusion it may have caused.