The equation T(t)=68e^(-0.0174)t+71 represents a temperature function, where T is the temperature in degrees Celsius and t is the time in hours.
To solve for T at a specific time t, substitute the value of t into the equation and simplify:
For example, if t=10 hours, then:
T(10) = 68e^(-0.0174)(10) + 71
T(10) = 68e^(-0.174) + 71
T(10) ≈ 63.6°C
Therefore, the temperature at 10 hours is approximately 63.6°C.
T(t)=68e^(-0.0174)t+71
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