T(t)=68e^(-0.0174)t+71

What is the temperature of the object after 1.5 hours?

1 answer

To find the temperature of the object after 1.5 hours, we need to substitute t=1.5 in the given equation:

T(1.5) = 68e^(-0.0174*1.5) + 71

T(1.5) = 68e^(-0.0261) + 71

Using a calculator, we can evaluate e^(-0.0261) as 0.974, and then multiply it by 68:

T(1.5) = 68 * 0.974 + 71

T(1.5) = 66.232 + 71

T(1.5) = 137.232

Therefore, the temperature of the object after 1.5 hours is approximately 137.232 degrees.