t A cart is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 4.0 m/s2. What is the magnitude of the cart’s displacement during the first 6.0 s of its motion?

Answer 1

To find the magnitude of the cart's displacement during the first 6.0 s of its motion, we can use the equation:

\[s = ut + \frac{1}{2}at^2\]

Where:
- s = displacement
- u = initial velocity = 5.0 m/s
- a = acceleration = 4.0 m/s^2
- t = time = 6.0 s

Plugging in the values, we get:

\[s = (5.0)(6.0) + \frac{1}{2}(4.0)(6.0)^2\]
\[s = 30 + 72\]
\[s = 102\]

Therefore, the magnitude of the cart's displacement during the first 6.0 s of its motion is 102 meters.