Systems of Linear Equations Unit Test the system of by graphing your of your what the like and what this you about the to the of equations y = z + 3; - 4s + k = 28

Answer 1

To plot the system of equations y = z + 3 and -4s + k = 28, we first need to rewrite them in slope-intercept form (y = mx + b) if possible.

For the first equation, y = z + 3 can be rewritten as z = y - 3. This equation does not have a fixed slope or y-intercept, so it is difficult to graph without specific values.

For the second equation, -4s + k = 28 can be rewritten as k = 4s + 28. This equation has a slope of 4 and a y-intercept of 28.

Since we cannot easily graph the first equation, let's focus on graphing the second equation. We can plot the y-intercept at (0, 28) and then use the slope of 4 to find another point on the line. With two points, we can draw the line representing the equation -4s + k = 28.

Overall, this system of equations does not seem to have a clear solution unless we have specific values for some of the variables. The graph may provide some visual insight into how the equations relate to each other, but without more information, it is difficult to determine any particular solution.