Systems of Linear Equations Online Practice

Question

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Question
For renting tables, Parties ‘R Us charges, C
, a $60 delivery fee and $4 per table, t
. Rob’s Rentals charges, C
, a $40 delivery fee and $6 per table, t
. Write the pair of linear equations that model this situation.(1 point)
Responses

Parties ‘R Us: C=60t+6
; Rob’s Rentals: C=40t+4
Parties ‘R Us: upper C equals 60 t plus 6 ; Rob’s Rentals: upper C equals 40 t plus 4

Parties ‘R Us: C=4t+40
; Rob’s Rentals: C=6t+60
Parties ‘R Us: upper C equals 4 t plus 40 ; Rob’s Rentals: upper C equals 6 t plus 60

Parties ‘R Us: C=4t+60
; Rob’s Rentals: C=6t+40
Parties ‘R Us: upper C equals 4 t plus 60 ; Rob’s Rentals: upper C equals 6 t plus 40

Parties ‘R Us: C=60t+4
; Rob’s Rentals: C=40t+6
Parties ‘R Us: upper C equals 60 t plus 4 ; Rob’s Rentals: upper C equals 40 t plus 6

Answer 1

To model the situation given in the problem, we need to set up the equations for each company's rental cost based on their charges.

1. Parties 'R Us charges a $60 delivery fee and $4 per table. This can be represented as: \[ C = 4t + 60 \]

2. Rob’s Rentals charges a $40 delivery fee and $6 per table. This can be represented as: \[ C = 6t + 40 \]

So, the correct pair of linear equations that model this situation is:

• Parties ‘R Us: \( C = 4t + 60 \)
• Rob’s Rentals: \( C = 6t + 40 \)

Thus, the answer is: Parties ‘R Us: C=4t+60; Rob’s Rentals: C=6t+40