Sx°3(x+1)dx

Answer 1

To integrate the given expression, we first distribute the 3 in the parentheses:

3x^2 + 3

Now we can integrate each term separately. The integral of 3x^2 is (3/3)x^3 = x^3, and the integral of 3 is 3x. Therefore, the final result of the integral of 3(x+1)dx is:

x^3 + 3x + C

where C is the constant of integration.