Swimming Pool On a certain hot summer's day, 471 people used the public swimming pool. The daily prices are $1.25 for children and $2.25 for adults. The receipts for

Question

admission totaled $860.75. How many children and how many adults swam at the public pool that day?

Answer 1

Let x be the number of children and y be the number of adults who swam at the public pool.
We know that x + y = 471 and 1.25x + 2.25y = 860.75.
To solve the equations, we can use substitution or elimination method. Let's use substitution:
Rearranging the first equation, we have x = 471 - y.
Substituting this into the second equation, we get 1.25(471 - y) + 2.25y = 860.75.
Expanding the equation, we get 588.75 - 1.25y + 2.25y = 860.75.
Combining like terms, we get 1.00y = 860.75 - 588.75.
Simplifying the right side, we get 1.00y = 272.
Dividing both sides by 1.00, we get y = 272.
Substituting this value back into the first equation, we get x + 272 = 471.
Subtracting 272 from both sides, we get x = 199.
Therefore, there were 199 children and 272 adults who swam at the public pool that day.