Sven is making a school supply display. Sven has 52 notebooks and 42 binders. Sven wants to group the supplies in the display so that there are an equal number of supplies in each group. If we know that Sven puts the same number of notebooks and the same number of binders into each group, how many groups did he display and how many of each item went into each group? Represent your answer using the Distributive Property of Multiplication over Addition.(1 point)

Question

Responses

Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26+21)
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Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2 left parenthesis 26 plus 21 right parenthesis .

Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52×42)
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Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 times 42 right parenthesis .

Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1(52+42)
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Sven made 1 group. He put all 52 notebooks and all 42 binders into that one group. Using the Distributive Property, the answer can be shown as 1 left parenthesis 52 plus 42 right parenthesis .

Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26×21)
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Answer 1

To determine how many groups Sven made and how many notebooks and binders he put into each group, we need to find the greatest common divisor (GCD) of the two numbers: 52 notebooks and 42 binders.

The GCD of 52 and 42 is 2. Thus, Sven can divide his supplies into 2 equal groups.

To find out how many notebooks and binders go into each group:

• For notebooks: \( \frac{52}{2} = 26 \)
• For binders: \( \frac{42}{2} = 21 \)

Therefore, Sven made 2 groups, putting 26 notebooks and 21 binders in each group.

Using the Distributive Property, we can represent this as: \[ 2(26 + 21) \]

So, the correct response is: Sven made 2 groups. He put 26 notebooks and 21 binders into each group. Using the Distributive Property, the answer can be shown as 2(26 + 21).