susan makes $5 per hour baby sitting and $7 per hour as a lifegaurd. her goal is to make at least $140. let x= the number of hours that susan babysits. let y = the number of hours that susan works as a lifeguard. which of the following represents three possible solutions to the problem?

Answer 1

A) (10, 10)
B) (8, 12)
C) (15, 3)
D) (20, 0)

To find the possible solutions, we need to find the values of x and y that satisfy the given conditions.

Since Susan makes $5 per hour babysitting and $7 per hour as a lifeguard, her total earnings can be represented as 5x + 7y.

According to the problem, Susan's goal is to make at least $140, so we have the inequality: 5x + 7y ≥ 140.

Let's check each option given:

A) (10, 10):
Substituting x = 10 and y = 10 into the inequality, we get: 5(10) + 7(10) = 50 + 70 = 120. This is less than 140, so option A is not a valid solution.

B) (8, 12):
Substituting x = 8 and y = 12 into the inequality, we get: 5(8) + 7(12) = 40 + 84 = 124. This is less than 140, so option B is not a valid solution.

C) (15, 3):
Substituting x = 15 and y = 3 into the inequality, we get: 5(15) + 7(3) = 75 + 21 = 96. This is less than 140, so option C is not a valid solution.

D) (20, 0):
Substituting x = 20 and y = 0 into the inequality, we get: 5(20) + 7(0) = 100 + 0 = 100. This is less than 140, so option D is not a valid solution.

None of the given options satisfy the condition of earning at least $140, so none of them represent possible solutions to the problem.