Surprisingly, very few athletes can jump more than 2.7 ft (0.82 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 0.82 m vertical jump. Then double it for the "hang-time" -- the time one's feet are off the ground.

Question

Surprisingly, very few athletes can jump more than 2.7 ft (0.82 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 0.82 m vertical jump. Then double it for the "hang-time" -- the time one's feet are off the ground.
Can you explain step by step please.

Graham · Answer

Use: d = (1/2) gt^2 Where: g = -9.8[m/s^2] Given: d = 0.82[m] Find: t Just rearrange the equation and substitute for the given values.

tonya · Answer

d=(1/2)gt^2 g=-9.8m/s^2 d=0.82 what about 2.7 ft?

Anonymous · Answer

27