Surface Area Unit Test

Question

8 of 158 of 15 Items

Question
Use the image to answer the question.

An illustration shows a 3 D triangular prism with the triangular face as a right triangle. The edges that are not visible are represented by dashed lines. The length and base of the triangular prism measures 30.5 centimeters and 27.9 centimeters. The perpendicular side of the triangular face measures 5.1 centimeter and the hypotenuse measures 28.4 centimeter.

A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.

(1 point)
S.A. =
cm2

Answer 1

To find the surface area of the triangular prism, we need to calculate the area of each of its faces and then add them together.

1. The area of the triangular face:
Area = (1/2) * base * height
Area = (1/2) * 27.9 cm * 5.1 cm
Area = 71.145 cm2

2. The area of the rectangular faces:
Area = 2 * base * length
Area = 2 * 27.9 cm * 30.5 cm
Area = 1701.9 cm2

Now, add the areas of all three faces together to get the total surface area of the triangular prism:
S.A. = 71.145 cm2 + 1701.9 cm2
S.A. = 1773.045 cm2

Rounded to the nearest whole number:
S.A. ≈ 1773 cm2

Therefore, 1773 cm2 of wrapping paper is needed to wrap the toy.