Surface Area of Triangular Prisms Practice

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Question
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An illustration shows a net version of a triangular prism. The net model shows 3 rectangles top to bottom. Identical triangles are attached to the left and right of the middle rectangle. Parts are labeled with measurements. The top and bottom rectangles have a length measuring 10 centimeters and a width measuring 5 centimeters. The perpendicular height from the top vertex of the triangle to the base measures 4 centimeters. The base of the triangle measures 5 centimeters. The base shares an edge with the middle rectangle.

What is the surface area of the net of the triangular prism?

(1 point)
square centimeters
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1 answer

To find the surface area of the net of the triangular prism, first calculate the area of each individual rectangle and triangle.

For the top and bottom rectangles:
Area = length x width
Area = 10 cm x 5 cm = 50 square cm (top rectangle)
Area = 10 cm x 5 cm = 50 square cm (bottom rectangle)

For the middle rectangle:
The length is the same as the top and bottom rectangles, so the area is also 50 square cm.

For the two triangles:
Area = (1/2) x base x height
Area = (1/2) x 5 cm x 4 cm = 10 square cm (one triangle)
Since there are two identical triangles, the total area for both triangles is 20 square cm.

Now, add up the area of all the shapes:
50 (top rectangle) + 50 (bottom rectangle) + 50 (middle rectangle) + 20 (two triangles) = 170 square cm

Therefore, the surface area of the net of the triangular prism is 170 square centimeters.