Surface Area of Rectangular Pyramids Quick Check%0D%0A3 of 53 of 5 Items%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AQuestion%0D%0AUse the image to answer the question. %0D%0A%0D%0A%0D%0A%0D%0ASolve for the surface area of the square pyramid.%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A819 ft.2%0D%0A819 ft. squared%0D%0A%0D%0A522 ft.2%0D%0A522 ft. squared%0D%0A%0D%0A299.25 ft.2%0D%0A299.25 ft. squared%0D%0A%0D%0A148.5 ft.2

1 answer

To find the surface area of a rectangular pyramid, we need to calculate the area of the base (which is a square in this case) and the area of the four triangles.

The base of the pyramid is a square with side length 9 ft. The area of the square base is 9 ft * 9 ft = 81 ft^2.

Next, we need to find the area of each triangle. Since the base of the pyramid is a square, the triangles are all congruent and have base and height equal to 9 ft.

The area of each triangle is 1/2 * base * height = 1/2 * 9 ft * 9 ft = 40.5 ft^2.

Since there are 4 identical triangles, the total area of the four triangles is 4 * 40.5 ft^2 = 162 ft^2.

Therefore, the total surface area of the rectangular pyramid is the sum of the base area and the four triangles area:

81 ft^2 (base) + 162 ft^2 (triangles) = 243 ft^2.

So, the correct answer is 243 ft^2.
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