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Original Question
Surface area of cylinders practiceAsked by kymari davis-shanks
Surface Area of Cylinders Practice
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Answered by
GPT-4o mini
Sure! To calculate the surface area of a cylinder, you need to know two measurements: the radius (r) of the base and the height (h) of the cylinder.
The formula for the surface area (SA) of a cylinder is:
\[
SA = 2\pi r(h + r)
\]
This formula accounts for the area of the two circular bases and the area of the curved surface.
1. **Area of the two bases**: \( 2\pi r^2 \)
2. **Area of the curved surface**: \( 2\pi rh \)
Putting it all together gives you the total surface area:
\[
SA = 2\pi r^2 + 2\pi rh = 2\pi r(h + r)
\]
### Let's practice with some examples!
**Example 1:**
- Radius (r) = 3 cm
- Height (h) = 5 cm
Calculate the surface area.
**Example 2:**
- Radius (r) = 4 m
- Height (h) = 10 m
Calculate the surface area.
### Solutions:
**Example 1:**
1. Calculate the surface area using the formula:
\[
SA = 2\pi(3)(5 + 3)
\]
\[
SA = 2\pi(3)(8)
\]
\[
SA = 48\pi \approx 150.8 \text{ cm}^2
\]
**Example 2:**
1. Calculate the surface area:
\[
SA = 2\pi(4)(10 + 4)
\]
\[
SA = 2\pi(4)(14)
\]
\[
SA = 112\pi \approx 351.9 \text{ m}^2
\]
Feel free to try your own examples or ask for more practice problems!
The formula for the surface area (SA) of a cylinder is:
\[
SA = 2\pi r(h + r)
\]
This formula accounts for the area of the two circular bases and the area of the curved surface.
1. **Area of the two bases**: \( 2\pi r^2 \)
2. **Area of the curved surface**: \( 2\pi rh \)
Putting it all together gives you the total surface area:
\[
SA = 2\pi r^2 + 2\pi rh = 2\pi r(h + r)
\]
### Let's practice with some examples!
**Example 1:**
- Radius (r) = 3 cm
- Height (h) = 5 cm
Calculate the surface area.
**Example 2:**
- Radius (r) = 4 m
- Height (h) = 10 m
Calculate the surface area.
### Solutions:
**Example 1:**
1. Calculate the surface area using the formula:
\[
SA = 2\pi(3)(5 + 3)
\]
\[
SA = 2\pi(3)(8)
\]
\[
SA = 48\pi \approx 150.8 \text{ cm}^2
\]
**Example 2:**
1. Calculate the surface area:
\[
SA = 2\pi(4)(10 + 4)
\]
\[
SA = 2\pi(4)(14)
\]
\[
SA = 112\pi \approx 351.9 \text{ m}^2
\]
Feel free to try your own examples or ask for more practice problems!
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