Surface Area of Cylinders Practice

Complete this assessment to review what you've learned. It will not count toward your grade.
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An illustration shows a rectangle of unknown height with a circle of radius 3 feet attached to its top left and a circle of radius 3 feet attached to its bottom right.

If the surface area of the net diagram of the right circular cylinder is 395.64 feet2 , find the height of the net diagram. Use 3.14 for π .

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To find the surface area of a cylinder, we use the formula:

Surface Area = 2πr^2 + 2πrh

In this case, we know the radius (r) is 3 feet and the surface area is 395.64 feet^2. We can set up the equation:

395.64 = 2(3.14)(3)^2 + 2(3.14)(3)h

Now, we can solve for h:

395.64 = 56.52 + 18.84h
338.12 = 18.84h
h ≈ 17.92 feet

Therefore, the height of the net diagram is approximately 17.92 feet.
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The surface area of a cylinder is given by the formula:

Surface Area = 2πr^2 + 2πrh

Given that the surface area of the cylinder is 395.64 feet^2, and the radius (r) is 3 feet, we can plug in the values and solve for the height (h):

395.64 = 2(3.14)(3)^2 + 2(3.14)(3)h
395.64 = 56.52 + 18.84h
337.12 = 18.84h
h = 337.12/18.84
h ≈ 17.9 feet

Therefore, the height of the net diagram is approximately 17.9 feet.
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