If a fear cylinder and a cone share the same radius, and the height of both shapes is twice the radius, then the volume of the two shapes can be compared.
The volume of the cylinder is given by the formula V_cylinder = πr^2h, where r is the radius and h is the height. Since the height is twice the radius, we can write h = 2r.
Therefore, V_cylinder = πr^2(2r) = 2πr^3.
The volume of the cone is given by the formula V_cone = (1/3)πr^2h. Substituting the value of h, we have V_cone = (1/3)πr^2(2r) = (2/3)πr^3.
Comparing the volumes of the fear cylinder and the cone, we can see that the volume of the cylinder is 2πr^3, while the volume of the cone is (2/3)πr^3. Therefore, the volume of the cylinder is 3 times greater than the volume of the cone.
In summary, if a fear cylinder and a cone have the same radius and the height of both shapes is twice the radius, then the volume of the cylinder is 3 times greater than the volume of the cone.
Supposed fear cylinder and a cone I'll share the same radius and the cylinder and The cone also share the same height which is twice the radius
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1 answer