Supposed f(x) = 6x'+ 2x - 7 and g(x) = 4x - 3.

What is (f - g)(x)?
Hint - Subtract f(x) and g(x), distribute the negative sign to g(x), and combine like terms.
Answer:
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1 answer

To find \((f - g)(x)\), we need to perform the subtraction \(f(x) - g(x)\).

Given: \(f(x) = 6x' + 2x - 7\)
\(g(x) = 4x - 3\)

Now, we will substitute \(g(x)\) into the subtraction:

\[ (f - g)(x) = f(x) - g(x) = (6x' + 2x - 7) - (4x - 3) \]

Now, distribute the negative sign:

\[ = 6x' + 2x - 7 - 4x + 3 \]

Next, combine the like terms. For the \(x\) terms:

\[ 2x - 4x = -2x \]

And for the constant terms:

\[ -7 + 3 = -4 \]

So the expression simplifies to:

\[ (f - g)(x) = 6x' - 2x - 4 \]

Thus, the final answer is:

\[ (f - g)(x) = 6x' - 2x - 4 \]