Question

Supposed f(x) = 6x'+ 2x - 7 and g(x) = 4x - 3.
What is (f - g)(x)?
Hint - Subtract f(x) and g(x), distribute the negative sign to g(x), and combine like terms.
Answer:
choose your answer... v

Answer 1

To find \((f - g)(x)\), we need to perform the subtraction \(f(x) - g(x)\).

Given:
\(f(x) = 6x' + 2x - 7\)
\(g(x) = 4x - 3\)

Now, we will substitute \(g(x)\) into the subtraction:

\[
(f - g)(x) = f(x) - g(x) = (6x' + 2x - 7) - (4x - 3)
\]

Now, distribute the negative sign:

\[
= 6x' + 2x - 7 - 4x + 3
\]

Next, combine the like terms. For the \(x\) terms:

\[
2x - 4x = -2x
\]

And for the constant terms:

\[
-7 + 3 = -4
\]

So the expression simplifies to:

\[
(f - g)(x) = 6x' - 2x - 4
\]

Thus, the final answer is:

\[
(f - g)(x) = 6x' - 2x - 4
\]