Supposed f(x) = 2" - 3x and g(x) = 1 - 2x.

What is (f + g)(x)?
Hint - Add f(x) and g(x) and combine like terms.
Answer:
choose your answer...

5 answers

To find \((f + g)(x)\), we need to add the functions \(f(x)\) and \(g(x)\) together.

Given:

  • \(f(x) = 2x - 3\)
  • \(g(x) = 1 - 2x\)

Now, we can calculate \((f + g)(x)\):

\[ (f + g)(x) = f(x) + g(x) \] \[ = (2x - 3) + (1 - 2x) \]

Now, combine the like terms:

\[ = 2x - 3 + 1 - 2x \] \[ = (2x - 2x) + (-3 + 1) \] \[ = 0 - 2 \] \[ = -2 \]

So, \((f + g)(x) = -2\).

Thus, the answer is: \(-2\)

2^n-5x + 1
2^n+ 5x+1
2^n-x-1
2^n-5x-1

It looks like you listed a few different expressions. However, it's unclear what you're asking for in relation to these expressions. If you are looking to find a particular operation (like addition or simplification) or if you're looking for which of these is equal to \((f + g)(x)\) calculated previously, please clarify.

Given that previously we calculated \((f + g)(x) = -2\), none of the provided expressions appear directly related to this calculation.

If you're looking to evaluate any of these expressions or perform a specific operation with them, please provide additional context.

Is it a , b , c or d??!

Thank you for your patience! Let's analyze the expressions you've listed in relation to the previous function calculation, which resulted in \((f + g)(x) = -2\):

The expressions you provided are:

  1. \(2^n - 5x + 1\)
  2. \(2^n + 5x + 1\)
  3. \(2^n - x - 1\)
  4. \(2^n - 5x - 1\)

From the previous calculation, we found:

\[ (f + g)(x) = -2 \]

Now we want to determine which of the choices equals \(-2\).

  1. For \(2^n - 5x + 1\), set it equal to \(-2\): \[ 2^n - 5x + 1 = -2 \implies 2^n - 5x = -3 \] (This does not necessarily imply \(2^n - 5x + 1 = -2\) for all \(n, x\))

  2. For \(2^n + 5x + 1\): \[ 2^n + 5x + 1 = -2 \implies 2^n + 5x = -3 \] (Same reasoning)

  3. For \(2^n - x - 1\): \[ 2^n - x - 1 = -2 \implies 2^n - x = -1 \implies 2^n = x - 1 \] (This also depends on \(n\) and \(x\), not equal to \(-2\))

  4. For \(2^n - 5x - 1\): \[ 2^n - 5x - 1 = -2 \implies 2^n - 5x = -1 \implies 2^n = 5x - 1 \] (Again, this does not universally equal \(-2\) for all \(n, x\))

None of these expressions are equal to a constant \(-2\) without additional context or specific values for \(n\) and \(x\).

If you need to select one based on the functional equality rather than just simply being \(-2\), it would still depend on those variable conditions.

Conclusion: If your task is to find if any of these expressions equal \(-2\) for some \(n\) and \(x\), none would directly do so without context. Let me know if you want to consider specific values for \(n\) or \(x\) in the options!