v(t) = v0 - 9.8t
see what you can do with that...
Suppose you throw an object from a great height, so that it reaches very nearly terminal velocity by time it hits the ground. By measuring the impact, you determine that this terminal velocity is -49 m/sec.
A. Write the equation representing the velocity v(t) of the object at time t seconds given the initial velocity v sub 0 and the fact that acceleration due to gravity is -9.8 m/sec^2.
B. Determine the value of k, the "continuous percentage growth rate" from the velocity equation, by utilizing the information given concerning the terminal velocity.
C. Using the value of k you derived above, at what velocity must the object be thrown upward if you want it to reach its peak height after 3 sec?
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