h = -16t^2 + 48t + 160.
a. V = Vo + g*Tr.
0 = 48 - 32Tr, Tr = 1.5 s. = Rise time.
b. h = -16*1.5^2 + 48*1.5 + 160 = 196 Ft. above gnd.
c. h = 0.5g*Tf^2.
196 = 16Tf^2, Tf^2 = 12.25, Tf = 3.5 s. = Fall time.
Tr + Tf = 1.5 + 3.5 = 5 s. = Time to hit gnd.
d. h = -16*2^2 + 48*2 + 160 =
Suppose you throw a ball up in the air from the top of a 160 foot building. It's height h in feet after t seconds is given by the function h= -8t^ + 48t + 160
a) When does the ball reach it's maximum height?
b) What is the ball's maximum height?
c) How long does it take before the ball comes back and hits the ground?
d) How high will the ball be at 2 seconds?
I know it's a quadratic equation but not sure how to set it up to find solutions by factoring or a parabola.
1 answer
1 answer