9 tiles in all, so
P(A,A) = 2/9 * 2/9
Suppose you choose a tile from a bag containing 2 A's, 3 B's, and 4 C's. You replace the first tile in the bag and then choose again. Find each probability.
P(A and A)
2 answers
i did the quiz and it said the answer was 2/27
Explanation according to the quiz:
P(A and B)
There are 2 A’s and 3 B’s out of a total of 9 tiles.
P(A)=2/9
P(B)=3/9
=1/3
P(A and B)=
2/9•1/3=2/27
Explanation according to the quiz:
P(A and B)
There are 2 A’s and 3 B’s out of a total of 9 tiles.
P(A)=2/9
P(B)=3/9
=1/3
P(A and B)=
2/9•1/3=2/27