suppose you can factor x^2+bx+c as (x+p)(x+q). If c<0, what could be possible values of p and q?

Question

a. p=-3 ,q=7
b. p=11 ,q=4
c. p=-2 ,q=-5
d. p=1 ,q=10

Answer 1

c. p=-2 ,q=-5

Answer 2

you wrong

Answer 3

as before,
since c=pq, that means that p and q have opposite signs.