The two you have written are correct.
The Ag2O + NaCl gives the same AgCl as the other equations you have. d forms the same Ag(NH3)2^2+ as in the part above it so that isn't a new equation either.
Solubility of Ag^+ from high to low.
Ag(NH3)2^2+
Ag2O
AgCl
AgI
Suppose you are given the following experimentally observed facts regarding the reactions of silver ion.
(a) Ag^+ reacts with Cl^- to give white AgCl (s)
(b) Ag^+ reacts with ammonia to give a quite stable complex ion, Ag(NH3)2^+
(c) a black suspension of solid silver oxide, Ag2O(s), shaken with NaCl solution, changes to white AgCl(s).
(d) AgCl(s) will dissolve when ammonia solution is added, but AgI(s) does not dissolve under these conditions.
Write equations for any net reacts in the cases above; then, based on these observations, arrange each of the substances AgCl, AgI, Ag2O, and Ag(NH3)2^+ in such an order that their solutions with water would give a successively decreasing concentration of Ag+.
so I got
a) Ag^+ (aq) + Cl^- (aq) <-> AgCl (s)
and
b) Ag^+ (aq) + 2NH3 (aq) <-> Ag(NH3)2^+ (aq)
I'm not sure if those are correct, and have no idea how to do the other two, and I don't know how to arrange them.
Please help!
1 answer