Let x be the width of the side parallel to the building. The other two sides then have length (80-x)/2
The area is y = x(40 - x/2)
y = 40x - (x^2/2)
You get maximum area when dy/dx = 0
40 -x = 0
x = 40
Table:
x y
20 600
30 750
39 799.5
40 800
41 799.5
50 750
60 600
suppose you are enclosing a rectangular area to create a rabbit cage. you have 80 ft of fence and want to build a pen with the largest possible area for your rabbit, so you build the cage using an existing building as one side.
make a table showing the areas for some selected values of x, and write a function that gives the area, y, as a function of the width, x
2 answers
afh