kx, where k is the constant of variation
Using the given information, we can find the value of k by plugging in the values of x and y:
9 = k(5)
Now, solve for k:
k = 9/5 = 1.8
So, the equation relating x and y is y = 1.8x.
To find the value of y when x = 15, plug in the value of x into the equation:
y = 1.8(15)
y = 27
Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x = 15.
Y =9 when X =5
Write a direct variation equation that relates x and y. (Simplify your​ answer.)
y=
3 answers
no
I apologize, let's start from the beginning.
Given that y varies directly with x, we can write the direct variation equation as:
y = kx,
where k is the constant of variation.
Using the given information that y = 9 when x = 5, we can substitute those values into the equation:
9 = k(5).
To find the value of k, we can divide both sides of the equation by 5:
9/5 = k.
So, the equation relating x and y is y = (9/5)x.
To find the value of y when x = 15, we substitute x = 15 into the equation:
y = (9/5)(15).
Simplifying, we get:
y = 27.
Therefore, when x = 15, y = 27.
Given that y varies directly with x, we can write the direct variation equation as:
y = kx,
where k is the constant of variation.
Using the given information that y = 9 when x = 5, we can substitute those values into the equation:
9 = k(5).
To find the value of k, we can divide both sides of the equation by 5:
9/5 = k.
So, the equation relating x and y is y = (9/5)x.
To find the value of y when x = 15, we substitute x = 15 into the equation:
y = (9/5)(15).
Simplifying, we get:
y = 27.
Therefore, when x = 15, y = 27.