Asked by elviria
                Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
3a. Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
.βx′=βx
.βx′=−βx
.βx′=(−1)xiβx
.βx′=(−1)x⋅xβx
βx′=βx⊕ei
            
            
        3a. Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
.βx′=βx
.βx′=−βx
.βx′=(−1)xiβx
.βx′=(−1)x⋅xβx
βx′=βx⊕ei
Answers
                    Answered by
            Final ;)
            
    Hi Elviria, do you have any answer for this exam?
    
                    Answered by
            Anonymous
            
    ƒÀxŒ=(−1)xiƒÀx 
    
                    Answered by
            Final ;)
            
    what is that?
    
                    Answered by
            s
            
    Another way to view it is to say that |ψ′⟩=Xi|ψ⟩ where Xi means X applied on the i-th qubit. We would like to claim that the application of Xi to the original state is effectively the same as applying some A to the i-th qubit after the Hadamard transform, i.e, H⊗n|ψ′⟩=H⊗nXi|ψ⟩=AiH⊗n|ψ⟩. What is A?
I
X
Z
H
XH
    
I
X
Z
H
XH
                    Answered by
            Anonymous
            
    3A .βx′=(−1)xiβx 
    
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