Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0 N, the second a force of 95.0 N, friction is 12.0 N, and the mass of the third child plus wagon is 21.0 kg.

Question

(c) Calculate the acceleration.
m/s2
(d) What would the acceleration be if friction is 20.0 N?

Answer 1

c. a = (95-75-12)/21 = 0.381 m/s^2.

d. a = (95-75-20)/21 = 0/21 = 0.