If each potato is 7.9 ± 1.1, then none of the BAGS of 6 will be between 7.5 and 8.5. For individual potatoes:
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two Z scores. Multiply by 100.
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 7.9 ounces and a standard deviation of 1.1 ounces.
Suppose Carl bags his potatoes in randomly selected groups of 6. What percentage of these bags should have a mean potato weight between 7.5 and 8.5 ounces?
1 answer
1 answer